fix some formatting issues

This commit is contained in:
Rowan 2025-03-31 20:46:38 -05:00
parent 5726e0d9c3
commit 8eaf2e5dcc

View file

@ -73,7 +73,7 @@ const none = Option.zero() // None
##### chain :: Option m => m a ~> (a -> m b) -> m b ##### chain :: Option m => m a ~> (a -> m b) -> m b
> Option\<T\>.chain\<U\>(fn: (value: T) -> Option\<U\>) -> Option\<U\> > Option\<T\>.chain\<U\>(fn: (value: T) -> Option\<U\>) -> Option\<U\>
Transform a `Option\<T\>` into `Option\<U\>` by applying `fn(T) -> Option\<U\>`. Transform a `Option<T>` into `Option<U>` by applying `fn(T) -> Option<U>`.
```js ```js
const some = Option.of(1) const some = Option.of(1)
@ -132,7 +132,7 @@ Represents a value which may fail.
##### of :: Result f => a -> f a ##### of :: Result f => a -> f a
> Result.of\<a\>(value: a) -> Result\<a, ()\> > Result.of\<a\>(value: a) -> Result\<a, ()\>
Creates a new `Ok\<T\>` from `T` Creates a new `Ok<T>` from `T`
```js ```js
const ok = Result.of(1) // Ok<number>(1) const ok = Result.of(1) // Ok<number>(1)
@ -150,7 +150,7 @@ const err = Result.zero() // Err<()>()
##### chain :: Result m => m a ~> (a -> m b) -> m b ##### chain :: Result m => m a ~> (a -> m b) -> m b
> Result\<T, E\>.chain\<U\>(fn: (value: T) -> Result<U, E>) -> Result\<U, E\> > Result\<T, E\>.chain\<U\>(fn: (value: T) -> Result<U, E>) -> Result\<U, E\>
Transform a `Result\<T, E\>` into `Result\<U, E\>` by applying `fn(T) -> Result\<U, E\>`. Transform a `Result<T, E>` into `Result<U, E>` by applying `fn(T) -> Result<U, E>`.
```js ```js
const ok = Result.of(1) const ok = Result.of(1)
@ -163,7 +163,7 @@ err.chain(() => Ok(1)) // Err(0)
##### map :: Result f => f a ~> (a -> b) -> f b ##### map :: Result f => f a ~> (a -> b) -> f b
> Result\<T, E\>.map\<U\>(fn: (value: T) -> U) -> Result\<U, E\> > Result\<T, E\>.map\<U\>(fn: (value: T) -> U) -> Result\<U, E\>
Transform a `Result\<T, E\>` into a `Result\<U, E\>` by applying `fn(T) -> U` Transform a `Result<T, E>` into a `Result<U, E>` by applying `fn(T) -> U`
```js ```js
const ok = Result.of(1) const ok = Result.of(1)